Topic 3: Forces And Newton's Laws

Lesson 3.3: Newton's Second Law And Weight

Official syllabus section covering Lesson 3.3: Newton's second law and weight within Topic 3: Forces and Newton's Laws: Newton's second law F = ma for straight-line motion and for motion in two perpendicular directions.; Weight as the force W = mg and motion in a straight line under gravity..

Lesson 3.3: Newton's Second Law and Weight

Introduction

Welcome to Lesson 3.3 of A-Level Mechanics. In this lesson, you will learn about Newton's second law of motion and the concept of weight. By the end of this lesson, you will be able to:

  • Understand and apply Newton's second law of motion $ F = ma $ for straight-line and two-dimensional motion.
  • Calculate weight using the formula $ W = mg $, where $ g = 9.8 \, \text{m/s}^2 $.
  • Explore the concept of equal and opposite forces as stated by Newton's third law.
  • Solve problems involving forces, mass, and acceleration in various contexts.

Let's start by understanding the essentials of Newton's second law.

Newton's Second Law of Motion

Newton's second law is a fundamental principle that describes the relationship between the force acting on an object, the mass of that object, and its acceleration. The law can be mathematically expressed as:

$$F = ma$$

Explanation of the Law

In this equation:

  • $ F $ is the net external force acting on the object measured in newtons (N).
  • $ m $ is the mass of the object measured in kilograms (kg).
  • $ a $ is the acceleration produced by the force measured in meters per second squared (m/s²).

The law indicates that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In simpler terms, a greater force leads to a greater acceleration, while a larger mass results in lesser acceleration for the same amount of force.

Worked Example 1: Calculating Acceleration

Problem Statement:

A car with a mass of 1,200 kg is subjected to a net force of 3,600 N. What is the acceleration of the car?

Solution:

To find the acceleration, we can rearrange the formula:

$$a = \frac{F}{m}$$

Plugging in the values:

$$a = \frac{3600 \, \text{N}}{1200 \, \text{kg}} = 3 \, \text{m/s}^2$$

Thus, the acceleration of the car is $ 3 \, \text{m/s}^2 $.

Common Misconception

Students often think that larger forces always lead to greater acceleration without considering the mass of the object. It's important to remember that when mass increases, the same force will produce less acceleration.

Motion in Two Perpendicular Directions

While Newton’s second law can be applied to motion along a single straight line, it can also be extended to two-dimensional motion. This often occurs in problems involving inclined planes or projectile motion.

Resolving Forces

When forces act in two perpendicular directions, we can resolve the net force into its components along those directions.

This can be done using trigonometry and understanding the angles involved.

Worked Example 2: Forces on an Inclined Plane

Problem Statement:

A block of mass 15 kg is resting on a frictionless inclined plane that makes an angle of $ 30^\circ $ with the horizontal. What is the acceleration of the block down the incline?

Solution:

To find the force acting down the incline, we first determine the gravitational force acting on the block:

$$W = mg = 15 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 147 \, \text{N}$$

Now, we will calculate the component of the weight acting parallel to the incline:

$$F_{\text{parallel}} = W \sin(30^\circ) = 147 \, \text{N} \times 0.5 = 73.5 \, \text{N}$$

Now apply Newton's second law:

$$a = \frac{F_{\text{parallel}}}{m} = \frac{73.5 \, \text{N}}{15 \, \text{kg}} = 4.9 \, \text{m/s}^2$$

Thus, the acceleration of the block down the incline is $ 4.9 \, \text{m/s}^2 $.

Weight and Gravity

Weight is the gravitational force exerted on an object and can be calculated using the formula:

$$W = mg$$

where:

  • $ W $ is the weight in newtons (N)
  • $ m $ is the mass in kilograms (kg)
  • $ g $ is the acceleration due to gravity, approximately $ 9.8 \, \text{m/s}^2 $.

Understanding Weight

Weight is dependent on mass and the strength of the gravitational field. On Earth, this is relatively constant at $ 9.8 \, \text{m/s}^2 $. This means that if you double the mass of an object, its weight will also double.

Worked Example 3: Finding Weight

Problem Statement:

What is the weight of a person with a mass of 70 kg?

Solution:

Using the formula for weight:

$$W = mg = 70 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 686 \, \text{N}$$

Thus, the weight of the person is $ 686 \, \text{N} $.

Common Misconception

One common misconception is the difference between mass and weight. Mass is a measure of the amount of matter in an object and remains constant regardless of location, whereas weight varies with the gravitational field strength.

Newton's Third Law of Motion

Newton's third law states that for every action, there is an equal and opposite reaction. This means that if one body exerts a force on another body, the second body exerts a force of equal magnitude but in the opposite direction on the first body.

Example of Newton's Third Law

Imagine a person standing on the ground. When the person exerts a downward force on the ground due to their weight, the ground exerts an equal force upward on the person. This is what allows us to stand without falling through the ground.

Conclusion

In this lesson, you have learned about Newton's second law and how it describes the relationship between force, mass, and acceleration. You also discovered how to calculate weight and its connection to gravity. Understanding these concepts will aid you in solving various physics problems involving motion and forces.

Study Notes

  • Newton's second law: $ F = ma $
  • Weight: $ W = mg $, where $ g \approx 9.8 \, \text{m/s}^2 $
  • Acceleration is directly proportional to force and inversely proportional to mass.
  • Forces can be resolved into components for two-dimensional motion.
  • Newton's third law: For every action, there is an equal and opposite reaction.

Practice Quiz

5 questions to test your understanding

Lesson 3.3: Newton's Second Law And Weight — A-Level Mechanics | A-Warded